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回复 6# oぃ夢ゞ舞風雲ヤ $ O* j; K: j0 d' w6 @( R0 R
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9 z8 |% H( [) U6 X Q7 b 现编一个,你只要左键依次点选封闭区域内部点后回车就出结果了:
- m; p0 S- U# O9 c, d(defun c:MJ ( / ENT ES I OBJ P0 S SS)+ f; R3 H3 Q. N8 V
(vl-load-com)7 k" u0 ]0 m1 I% d( z
(command "vscurrent" "C")# _( t4 c. p: \. h
(princ "\n ****本程序为求多个封闭区域的面积之和****")
$ D0 l9 S! f" @. l: U _+ ^: C (setq ss (ssadd))
- V; X' z1 ~! n6 j* ~9 r9 I, E (while (setq p0 (getpoint"\n拾封闭区域取内部点:<退出>"))
( j! R( B1 \7 E: |& {' X (COMMAND "._BOUNDARY" "A" "O" "R" "" p0 "")
$ i6 ~. G) t6 k' j; o' _. m (ssadd (entlast) ss)
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(setq i 0 ES 0)) W: G1 Y4 w0 {! V9 T' T
(repeat (sslength ss)5 x5 l, ~1 E1 ~; u( f" n/ t' m; v7 `
(setq ent (ssname ss i))
/ B2 \+ b) K' l. a s$ X (setq obj (vlax-ename->vla-object ent))" u. h' T0 W; |& p8 ?
(setq s (vla-get-Area obj))" i% N7 w- Y$ _4 m% \
(setq es (+ es s))8 d# Z9 {; ^' o- J" U/ I
(setq i (1+ i))/ k* w/ f) Y1 U- T1 m6 n* u
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(command "erase" (ssget "X" '((0 . "REGION"))) "")
: z) g- p4 e/ n6 y (command "vscurrent" "2")/ w, c+ Q2 |/ |' s# n2 G
(princ (strcat "总面积为:" (rtos es)))
; J: O6 m7 _ J I# A: h (princ)
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