1.在R﹦38的圆中作线段OA﹦25,O为圆心.
( Y' x* v1 S0 s2.过A作线段AB交圆于B.并使∠OAB﹦80°.
9 ]0 K- X) X: C; t& L; b8 V. h3.过AB中点C作线段CO,以CO为轴线作析线OAB的对称折线OA′B′.
; |% f6 B% k2 @' {6 K4.取接AA′,A′B.△ABA′为所求的直角三角形.8 Y0 A, A3 }4 V
查询结果：BA′﹦a﹦14.8786+ v, `; }9 _: ]# D. m) F
A′A﹦b﹦29.7764* C$ |- I; [' Y7 B8 f# p& r
AB﹦c﹦33.2868 |
发表于 2008-1-23 19:51
发表于 2008-2-5 20:21
